The circle in the figure below has a radius of r and center at C. The distance from A to B is x, the distance from A to D is y, and the length of arc BD is s. Redraw the figure, label it as indicated, and then solve the problem.

If A = 45°, s = 18, and r = 14, find y. (Round your answer to the nearest whole number.)

Respuesta :

Answer: y=19

Step-by-step explanation:

The figure of the triangle is attached and we have the following data:

[tex]A=45\°[/tex]

[tex]s=18[/tex] is the length of arc

[tex]r=14[/tex] is the radius

This problem can be solved by the Law of Sines:

[tex]\frac{sin A}{r}=\frac{sin C}{y}=\frac{sin D}{r+x}[/tex]

In order to find [tex]C[/tex], we will use the formula of the length of arc:

[tex]s=\frac{2 \pi r C}{360\°}[/tex]

Then: [tex]C=\frac{360\° s}{2 \pi r}[/tex]

[tex]C=\frac{360\° (18)}{2 \pi (14)}=73.66\°[/tex]

Returning to the Law of Sines:

[tex]\frac{sin A}{r}=\frac{sin C}{y}[/tex]

Finding [tex]y[/tex]:

[tex]y=\frac{sin C r}{sin A}[/tex]

[tex]y=\frac{sin (73.66\°) 14}{sin (45\°)}[/tex]

Finally:

[tex]y=18.99 \approx 19[/tex]

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