Question

Write a function called check_nums that takes a list as its parameter, and contains a while loop that only stops once the element of the list is the number 7. What is returned is a list of all of the numbers up until it reaches 7.

Answer 1

Answer:

Following are the program in the Python Programming Language:

def check_nums(length): #define function

 my_lst=[]  #set list type variable

 n=0  #set integer type variable

 while(length[n] != 7): #set the while loop  

   my_lst.append(length[n])  #append liat in my_lst

   n+=1  #increament in n

   if(len(length)==n): #set if condition

     break  #break the loop

 return my_lst  #return the list

l=[4,6,2,55,16,7,81]  #set list variable and assign list init

print(check_nums(l)) #call and print the function

Output:

[4, 6, 2, 55, 16]

Explanation:

Here, we define a function "check_nums()" and pass an argument in its parentheses inside the function,

• we set list data type variable "my_lst" and integer type variable "n"
• we set while loop and pass the condition is the variable "length[n]" is not equal to the 7 then, the value of "length[n] " is appends to the variable "my_lst" and increment in the variable "n" by 1.
• we set if condition and check when the length of the variable "length" is equal to the variable "n" then, break the loop and return the value of "my_lst".

Finally, set the list type variable "l" and assign the list of numeric value in it then, call and print the function "check_nums"

Answer 2

In this exercise, using the knowledge of computational language in python, we have that this code will be written as:

The code is in the attached image.

We can write the python as:

def check_nums(length):

my_lst=[]  

n=0  

while(length[n] != 7):  

  my_lst.append(length[n])  

  n+=1  

  if(len(length)==n):

    break  

return my_lst  

l=[4,6,2,55,16,7,81]  

print(check_nums(l))

See more about python at brainly.com/question/13437928