Quadratic function help?

Answer:
12 units
Step-by-step explanation:
Let the equation of the parabola is [tex]y = \frac{1}{48} x^{2}[/tex]
So, [tex]x^{2} = 48y[/tex] ........... (1)
Now, the general form of a parabola having vertex at origin and axis parallel to positive y-axis is given by
[tex]x^{2} = 4ay[/tex] ........ (2)
Now, comparing equation (1) and equation (2) we get, a = 12
We know that the focal length of the parabola [tex]x^{2} = 4ay[/tex] i.e. distance between the vertex and the focus is a.
Therefore, the focal length of the parabola (1) is 12 units. (Answer)