Answer:
Two thirds the number of moles of hydrogen
Explanation:
The balanced reaction is
3H₂ + N₂ → 2NH₃
So 1 mol of nitrogen gas reacts completely with 3 moles of hydrogen gas, to produce 2 moles of ammonia.
If equal moles of nitrogen and hydrogen are combined, then hydrogen would be the limiting reactant. Let's say we have 3 moles of each reactant, one mol of N₂ reacts with the 3 moles of H₂ and produces 2 moles of NH₃, and 2 moles of N₂ would remain. So the answer is two thirds the number of moles of hydrogen.
Answer:
The number of moles NH3 produced is two thirds of moles of hydrogen.
Explanation:
Step 1: Data given
Number of moles H2 = Number of moles N2
Step 2: The balanced equation
3H2 + N2 → 2NH3
Step 3: Calculate mol NH3 produced
For 1 mol N2 consumed, we need 3 moles of H2, to produce 2 mol of NH3
H2 is the limiting reactant. This will be completely consumed.
N2 is in excess. There will be consumed 1/3 of moles of H2
The mole ratio H2:NH3 = 3:2
The number of moles NH3 produced is two thirds of moles hydrogen.
The number of moles N2 is one third of moles hydrogen.
