Respuesta :
Answer:
1) k = 1.31 10⁻⁷ m, 2) z = 59,875 (2n + 1) 10⁻⁹ m 3) Ex = 3.12 10⁻³ N /C
Explanation:
The equation of a wave is
y = A sin (kz -wt)
Where A is the amplitude, k the wave number and w the angular velocity.
1) we calculate the wave number
k = 2π /λ
k = 2π / 479 10⁻⁹
k = 1.31 10⁻⁷ m
.2) the points where the magnetic field is maximum occurs when the sine function is maximum
sin (kz - et) = + -1
kz-wt = 90º = π/4 (2n + 1) n integerr
z = (π / 4) / k
z = (π / 4) λ / 2π)
z = λ/8 (2n + 1)
z = 479 10⁻⁹ / 8 (2n + 1)
z = 59,875 (2n + 1) 10⁻⁹ m
3) the electric and magnetic fields are related
E = c B
Therefore we can calculate the maximum electric field from the magnetic field
Bmax = B1 (i ^ + j ^)
Ex = c B1 i ^
Ex = 3 10⁸ 10.4 1⁻⁶
Ex = 3.12 10⁻³ N /C
4) E (x, y) = E1 sin (k z -wt)
E1 = c B1
E (x, y) = E1
Therefore the component Ey must be maximum
Ey = c B1
Ey = 3 108 10.4 10-6
Ey = 312 10-3
The value of k is [tex]\rm 1.31\times10^{-7} \ m[/tex], [tex]\rm z_{max}=1.199\times10^7[/tex] meter, [tex]\rm E_{max}= 22.06\times 10^2 \ N/c[/tex], and [tex]\rm \left|\vec{_{E_y}} \right| =22.06\times10^2 \ N/c[/tex]
What is a magnetic field?
The magnetic field is defined as the field the magnetic materials generate or when an electric charge moves in a field region that generates the magnetic field.
We have a magnetic field in a plane monochromatic electromagnetic wave.
The equation for the wave is given by:
[tex]\rm y = a \ sin (kz-wt)[/tex]
Where A = Amplitude of the wave
k = Wave-number
w = Angular velocity
For the k, we know:
[tex]\rm k =\frac{2\pi}{\lambda}[/tex]
[tex]\rm k =\frac{2\pi}{479\times10^{-9}}[/tex] [tex]\rm (\lambda = 479 \ nm = 479\times10^{-9} \ meter)[/tex]
[tex]\rm k = 1.31\times10^{-7} \ m[/tex]
The point where the magnetic field is maximum:
[tex]\rm sin(kz-wt)=\pm1[/tex] or
kz - wt = π/2
kz = π/2 ( t = 0)
[tex]\rm z = \frac{\pi}{2k}[/tex]
[tex]\rm z = \frac{\pi}{2\times1.31\times10^{-7}}[/tex] ([tex]\rm k = 1.31\times10^{-7} \ m[/tex])
[tex]\rm z_{max}=1.199\times10^7[/tex] m
For the [tex]\rm E_{max}[/tex] = [tex]\rm c\times[/tex][tex]\rm B_{max}[/tex] ( c is the speed of light)
[tex]\rm B_1 = 10.4\times10^{-6 } \ T[/tex]
[tex]\rm B_{max}= 10.4\times 10^{-6}\times\frac{1}{\sqrt{2} } \ T[/tex]
[tex]\rm E_{max}=3\times10^8\times\rm 10.4\times 10^{-6}\times\frac{1}{\sqrt{2} }[/tex]
[tex]\rm E_{max}= 22.06\times 10^2 \ N/c[/tex]
For [tex]\rm E_y[/tex]
[tex]\rm \left|\vec{_{E_y}} \right| =\frac{cB_1}{\sqrt{2} }sin(kz_{max)}[/tex]
[tex]\rm \left|\vec{_{E_y}} \right| =22.06\times10^2 \ N/c[/tex]
Thus, the value of k is [tex]\rm 1.31\times10^{-7} \ m[/tex], [tex]\rm z_{max}=1.199\times10^7[/tex] meter, [tex]\rm E_{max}= 22.06\times 10^2 \ N/c[/tex], and [tex]\rm \left|\vec{_{E_y}} \right| =22.06\times10^2 \ N/c[/tex]
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