A certain half-reaction has a standard reduction potential =E0red+0.13V . An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.10V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.

Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. yes, there is a minimum. =E0red V no minimum

Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. yes, there is a maximum. =E0red V no maximum

By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Note: write the half reaction as it would actually occur at the cathode. e

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Answer:

The minimum standard reduction potential of the cathode is 1.23 V. There is no maximum standard reduction potential of the cathode.

O₂(g) + 4 H⁺(aq) + 4 e⁻ ⇒ 2 H₂O(l)

Explanation:

The standard cell potential (E°) is the difference between the reduction potential of the cathode (E°red, cat) and the reduction potential of the anode (E°red, an).

E° = E°red, cat - E°red, an

If E°red, an = 0.13 V and E° = 1.10 V,

E°red, cat = E° + E°red, an = 1.10 V + 0.13 V = 1.23 V

The minimum standard reduction potential of the cathode is 1.23 V. There is no maximum standard reduction potential of the cathode.

A possible cathode is the one made of O₂/H₂O, whose reduction potential is E°red = 1.23 V. The reduction that would take place in the cathode is:

O₂(g) + 4 H⁺(aq) + 4 e⁻ ⇒ 2 H₂O(l)

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