Question

A car slams on its brakes creating an acceleration of -3.2 m/s2 it comes to a rest after traveling a distance of 210 m what was it's velocity before it began to accelerate

Answer 1

The initial velocity of the car is 36.6 m/s

Explanation:

The motion of the car is a uniformly accelerated motion (=constant acceleration), therefore we can apply suvat equations:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem, we have:

v = 0 is the final velocity (the car comes to a stop)

$a=-3.2 m/s^2$ is the acceleration

s = 210 m is the displacement of the car

Solving for u, we find the initial velocity:

$u=\sqrt{v^2-2as}=\sqrt{0-(2)(-3.2)(210)}=36.6 m/s$

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