You throw a 50.0g blob of clay directly at the wall with an initial velocity of -5.00 m/s i. The clay sticks to the wall, and the collision takes about 20.0 ms (2.00 x 10^-2 s). a) What is the change in momentum for the blob of clay?

Respuesta :

Answer:0.25 kg-m/s

Explanation:

Given

mass of blob [tex]m=50 gm [/tex]

initial velocity [tex]u=-5 m/s\ \hat{i}[/tex]

time of collision [tex]t=20 ms[/tex]

we know Impulse is equal to change in momentum

initial momentum [tex]P_i=mu[/tex]

[tex]P_i=50\times 10^{-3}\times (-5)=-0.25 kg-m/s[/tex]

Final momentum [tex]P_f=50\times 10^{-3}v[/tex]

[tex]P_f=0[/tex] as final velocity is zero

Impulse [tex]J=P_f-P_i[/tex]

[tex]J=0-(-0.25)[/tex]

[tex]J=0.25 kg-m/s[/tex]

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