Question

The quadrilateral shown is a rhombus. If AB = 17 and AE = 8, what is the measure of BE

Answer 1

Answer:

$BE=15\ units$

Step-by-step explanation:

we know that

In a rhombus the diagonals are perpendicular

so

The triangle ABE is a right triangle

see the attached figure to better understand the problem

Applying the Pythagoras Theorem to the right triangle ABE

$AB^2=AE^2+BE^2$

where

AB is the hypotenuse of the right triangle (greater side)

AE and BE are the legs of the right triangle

we have

$AB=17\ units\\AE=8\ units$

substitute

$17^2=8^2+BE^2$

solve for BE

$289=64+BE^2$

$BE^2=289-64$

$BE^2=225$

$BE=15\ units$

Answer 2

Answer:

C) 16

Step-by-step explanation: