Answer:
14 g
Explanation:
First, we have to calculate the partial pressure of N₂. We know that the air is 80% nitrogen by volume, which, for a gas mixture, means that the mole fraction of N₂ is 0.80.
We can calculate the partial pressure of N₂ (pN₂) using the following expression:
pN₂ = P . x(N₂)
where,
P is the total pressure
x(N₂) is the mole fraction of N₂
pN₂ = 1.1 atm . 0.80 = 0.88 atm
Then, we can calculate the moles of N₂ using the ideal gas equation.
[tex]P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.88atm.14L}{(0.082atm.L/mol.K).(25 +273)K} =0.50mol[/tex]
Considering that the molar mass of N₂ is 28.01 g/mol, the mass of N₂ is:
[tex]0.50mol.\frac{28.01g}{mol} =14g[/tex]