Respuesta :
Answer:
The reactions are shown in the explanation
Explanation:
The net bronsted equation will include the acid / base and its dissciated product. (conjugate base or acid and hydrogen or hydroxide ions)
a) Vinegar
[tex]CH{3}COOH+H_{2}O--->CH{3}COO^{-}+H_{3}O^{+}[/tex]
b) bleach
[tex]NaOCl+H_{2}O--->HOCl+Na^{+}+OH^{-}[/tex]
c) ammonia
[tex]NH_{3}+H_{2}O--->NH_{4}^{+}+OH^{-}[/tex]
d)Vitamin C
[tex]H_{2}C_{6}H_{6}O_{6}+H_{2}O--->HC_{6}H_{6}O_{6}^{-}+H_{3}O^{+}[/tex]
e)Citric acid
[tex]H_{3}C_{6}H_{6}O_{7}+H_{2}O--->H_{2}C_{6}H_{6}O_{7}^{-}+H_{3}O^{+}[/tex]
f) Washing soda
[tex]Na_{2}CO_{3} +H_{2}O--->NaHCO_{3}^{-}+OH^{-}[/tex]
The net Brønsted equations that show the acidic or basic nature of the following solutions in water are:
(a) HC₂H₃O₂ + H₂O ⇒ C₂H₃O₂⁻ + H₃O⁺
(b) OCl⁻ + H₂O ⇒ HClO + OH⁻
(c) NH₃ + H₂O ⇒ NH₄⁺ + OH⁻
(d) H₂C₆H₆O₆ + H₂O ⇒ HC₆H₆O₆⁻ + H₃O⁺
(e) H₃C₆H₅O₇ + H₂O ⇒ H₂C₆H₅O₇⁻ + H₃O⁺
(f) CO₃²⁻ + H₂O ⇒ HCO₃⁻ + OH⁻
According to Brønsted-Lowry acid-base theory:
- An acid is a species that donates H⁺.
- A base is a species that accepts H⁺.
Let's consider the net Brønsted equations for the following species.
(a) vinegar (acetic acid, HC₂H₃O₂)
HC₂H₃O₂ is an acid according to the following equation.
HC₂H₃O₂ + H₂O ⇒ C₂H₃O₂⁻ + H₃O⁺
(b) bleach (sodium hypochlorite, NaOCl)
NaOCl is a base according to the following equation.
OCl⁻ + H₂O ⇒ HClO + OH⁻
(c) ammonia (NH₃)
NH₃ is a base according to the following equation.
NH₃ + H₂O ⇒ NH₄⁺ + OH⁻
(d) Vitamin C (ascorbic acid, H₂C₆H₆O₆)
H₂C₆H₆O₆ is an acid according to the following equation.
H₂C₆H₆O₆ + H₂O ⇒ HC₆H₆O₆⁻ + H₃O⁺
(e) lemon juice (citric acid, H₃C₆H₅O₇)
H₃C₆H₅O₇ is an acid according to the following equation.
H₃C₆H₅O₇ + H₂O ⇒ H₂C₆H₅O₇⁻ + H₃O⁺
(f) washing soda (sodium carbonate, Na₂CO₃)
Na₂CO₃ is a base according to the following equation.
CO₃²⁻ + H₂O ⇒ HCO₃⁻ + OH⁻
The net Brønsted equations that show the acidic or basic nature of the following solutions in water are:
(a) HC₂H₃O₂ + H₂O ⇒ C₂H₃O₂⁻ + H₃O⁺
(b) OCl⁻ + H₂O ⇒ HClO + OH⁻
(c) NH₃ + H₂O ⇒ NH₄⁺ + OH⁻
(d) H₂C₆H₆O₆ + H₂O ⇒ HC₆H₆O₆⁻ + H₃O⁺
(e) H₃C₆H₅O₇ + H₂O ⇒ H₂C₆H₅O₇⁻ + H₃O⁺
(f) CO₃²⁻ + H₂O ⇒ HCO₃⁻ + OH⁻
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