Question

Dinitrogen oxygen, N2O, has two double bonds. The general structure is N=N=O. The formal charge on the oxygen atom isA.) 0B.) +1C.) +2D.) -1

Answer 1

Answer:

A.) 0

Explanation:

Dinitrogen oxygen ($N_2O$)

Valence electrons of oxygen = 6

Valence electron of nitrogen = 5

The total number of the valence electrons  = 2(5) + 6 = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So, The Lewis structure is shown in image below.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

Formal charge for oxygen:

$\text{Formal charge}=6-4-\frac{4}{2}=0$