Answer:
49.6°
Explanation:
[tex]I_0[/tex] = Unpolarized light
[tex]I_2[/tex] = Light after passing though second filter = [tex]0.21I_0[/tex]
Polarized light passing through first filter
[tex]I_1=\frac{I_0}{2}[/tex]
Polarized light passing through second filter
[tex]I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.21I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.21I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.21\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.42}\\\Rightarrow \theta=49.6^{\circ}[/tex]
The angle between the two filters is 49.6°