Answer:
22.02°C
Explanation:
P = Power output = 30 kW
Volume flow rate of water = [tex]1.49\times 10^{-4}\ m^3/s[/tex]
S = Specific heat of water = 4.186 kJ/mol°C
[tex]T_i[/tex] = Initial temperature = 10°C
[tex]T_f[/tex] = Final temperature
Total volume of water is
[tex]v=4\times 1.49\times 10^{-4}\\\Rightarrow v=5.96\times 10^{-4}\ m^3/s[/tex]
Mass flow rate is
[tex]m=\rho\times v\\\Rightarrow m=1000\times 5.96\times 10^{-4}\\\Rightarrow m=0.596\ kg/s[/tex]
Heat is given by
[tex]\frac{q}{t}=\frac{m}{t}S\Delta T\\\Rightarrow 30=0.596\times 4.186(T_f-10)\\\Rightarrow T_f=\frac{30}{0.596\times 4.186}+10\\\Rightarrow T_f=22.02\ ^{\circ}C[/tex]
The maximum possible temperature of the hot water that each showering resident receives is 22.02°C