Emma is saving money for college. She has $800 and wants to deposit it into 2 different savings accounts. She decides to deposit $500.00 into an account, Account I, which earns 2.5% annual simple interest. She will then deposit $300 into an account, Account II, which earns 2 1 4 % interest compounded annually. If Emma makes no other deposits or withdrawals, what is the total amount of money she will have at the end of 3 years?

Respuesta :

Answer:

The amount would be $ 858.21

Step-by-step explanation:

Given,

In first account,

Deposited amount, [tex]P_1[/tex] = $ 500,

Annual simple interest, [tex]r_1[/tex] = 2.5%,

Number of years, [tex]t_1[/tex] = 3 years,

So, the amount after 3 years,

[tex]A_1 = P_1 + \frac{P_1\times r_1\times t_1}{100}[/tex]

[tex]A_1 = 500 + \frac{500\times 2.5\times 3}{100}[/tex]

[tex]A_1 = 500 + \frac{3750}{100}[/tex]

[tex]A_1 = 500 + 37.50[/tex]

[tex]A_1 = 537.5[/tex]

In second account,

Deposited amount, [tex]P_2[/tex] = $ 300,

Annual compound interest, [tex]r_2[/tex] = 2.25%, ( ∵ [tex]2\frac{1}{4}=2.25[/tex] )

Number of years, [tex]t_2[/tex] = 3 years,

So, the amount after 3 years,

[tex]A_2 = P_2(1 + \frac{r_2}{100})^{t_2}[/tex]

[tex]A_2= 300(1+\frac{2.25}{100})^3[/tex]

[tex]A_2 = 300(1+0.0225)^3[/tex]

[tex]A_2 = 300(1.0225)^3[/tex]

[tex]A_2 = 320.71[/tex]

Hence, the total amount,

[tex]A=A_1 + A_2 = 537.5 + 320.71 = \$ 858.21[/tex]

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