Answer:
The amount would be $ 858.21
Step-by-step explanation:
Given,
In first account,
Deposited amount, [tex]P_1[/tex] = $ 500,
Annual simple interest, [tex]r_1[/tex] = 2.5%,
Number of years, [tex]t_1[/tex] = 3 years,
So, the amount after 3 years,
[tex]A_1 = P_1 + \frac{P_1\times r_1\times t_1}{100}[/tex]
[tex]A_1 = 500 + \frac{500\times 2.5\times 3}{100}[/tex]
[tex]A_1 = 500 + \frac{3750}{100}[/tex]
[tex]A_1 = 500 + 37.50[/tex]
[tex]A_1 = 537.5[/tex]
In second account,
Deposited amount, [tex]P_2[/tex] = $ 300,
Annual compound interest, [tex]r_2[/tex] = 2.25%, ( ∵ [tex]2\frac{1}{4}=2.25[/tex] )
Number of years, [tex]t_2[/tex] = 3 years,
So, the amount after 3 years,
[tex]A_2 = P_2(1 + \frac{r_2}{100})^{t_2}[/tex]
[tex]A_2= 300(1+\frac{2.25}{100})^3[/tex]
[tex]A_2 = 300(1+0.0225)^3[/tex]
[tex]A_2 = 300(1.0225)^3[/tex]
[tex]A_2 = 320.71[/tex]
Hence, the total amount,
[tex]A=A_1 + A_2 = 537.5 + 320.71 = \$ 858.21[/tex]