Answer:
There are 1.34x10²³ molecules in the flask.
Explanation:
The flask volume is 5.00 L and the air is at standard temperature and pressure.
We must use the Ideal Gas Law to solve this.
Standard temperature and Pressure are 273.15 K and 1 atm.
P . V = n . R . T
1 atm . 5 L = n . 0.082 L.atm/mol.K . 273.15K
(1atm . 5L) / (0.082 mol.K/L.atm .273.15K) = n
0.223 mol = n
This is the quantity of air in the flask. You should know by Avogadro that 1 mol has 6.02x10²³ molecules so, let's make the rule of three:
1 mol ____ 6.02x10²³ molecules
0.223 moles ______ (0.223 . 6.02x10²³) = 1.34x10²³ molecules