All else being equal, if you cut the sample size in half, how does this affect the margin of error when using the sample to make a statistical inference about the mean of the normally distributed population from which it was drawn? . The margin of error is multiplied by . The margin of error is multiplied by . The margin of error is multiplied by 0.5. The margin of error is multiplied by 2.

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Answer:

The margin of error is multiplied by [tex]\sqrt{2}[/tex]

Step-by-step explanation:

margin of error (ME) from the mean can be calculated using the formula

ME=[tex]\frac{z*s}{\sqrt{N} }[/tex] where

  • z is the corresponding statistic of the given confidence level
  • s is the standard deviation of the sample (or of the population if it is known)
  • N is the sample size

Since margin of error is proportional with inverse of [tex]\sqrt{N}[/tex],

if we cut the sample size in half, the margin of error is multiplied by [tex]\sqrt{2}[/tex].

Answer:

That would be The margin of error is multiplied by 2.

Step-by-step explanation:

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