Answer:
The correct answer will be option-B
Explanation:
The number of different possible gametes produced in this dihybrid genotype during independent assortment depends on the heterozygous pairs at a single locus.
During independent assortment, each heterozygous pair of alleles separate forming 2 gametes whereas homozygous pair of alleles form only 1 type of gamete.
In the given question with genotype AaBbCCDdEE contains:
1. Three pairs of heterozygous pairs- Aa, Bb and Dd
2. Two homozygous pairs- CC and EE
So, during independent assortment, the gametes formed will be-
1. Aa will segregate to form- A and gametes (2 gametes)
2. Bb will segregate to form- B and B gametes (2 gametes)
3. Dd will segregate to form- D and d gametes (2 gametes)
4. CC will segregate to form- C only ( 1 gamete)
5. EE will segregate to form- E only ( 1 gamete)
Thus, 8 different types of gametes are produced.