Question

A weather balloon is inflated to a volume of 28.1 L at a pressure of 745 mmHg and a temperature of 29.0 ∘C. The balloon rises in the atmosphere to an altitude where the pressure is 380. mmHg and the temperature is -16.3 ∘C. Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.

Answer 1

Answer:

$V_2=46.8 L$

Explanation:

For these changes in pressure and temperature, assuming that the gases in the balloon are ideal, we can apply the general equation of gases:

$\frac{P_1*V_1}{T_1}=\frac{P_2*V_2}{T_2}$

Been 1 the initial conditions and 2 the final ones:

$\frac{745 mmHg*28.1L}{302K}=\frac{380 mmHg*V_2}{256.7K}$

$V_2=\frac{745 mmHg*28.1L*256.7K}{380 mmHg*302K}$

$V_2=46.8 L$