Question

Can someone help me with this????? The question is attached in the image

Answer 1

Answer:

See explanation

Step-by-step explanation:

Since $\overline{CB}$ is parallel to $\overline {ED},$ then

• angles EDF and CBF are congruent as alternate interior angles when parallel lines  $\overline{CB}$ is parallel to $\overline {ED}$ intersect by transversal DB;

• angles DEF and BCF are congruent as alternate interior angles when parallel lines  $\overline{CB}$ is parallel to $\overline {ED}$ intersect by transversal CE.

Consider triangles CBF and EDF. In these triangles:

• $\angle EDF\cong \angle CBF$ (proven);
• $\angle FED\cong \angle FCB$ (proven);
• $\overline{CB}\cong \overline {ED}$ (given).

Thus, triangles CBF and EDF are congruent by ASA postulate.