Question

What is PA
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Answer 1

Answer:

3

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : $PK^{2}=PE^{2}+KE^{2}$

⇒$PE^{2}=PK^{2}-KE^{2}$

⇒$PE=\sqrt{PK^{2}-KE^{2} }$

⇒$PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }$

⇒$PE=3$

Therefore, $PA=3$