Answer:
8.67807 N
34.7123 N
Explanation:
m = Mass of shark = 92 kg
[tex]\rho_{se}[/tex] = Density of seawater = 1030 kg/m³
[tex]\rho_{f}[/tex] = Density of freshwater = 1000 kg/m³
[tex]\rho_{sh}[/tex] = Density of shark = 1040 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
Net force on the fin is (seawater)
[tex]F_n=mg-V_s\rho_{se}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{se}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1030\times 9.81\\\Rightarrow F_n=8.67807\ N[/tex]
The lift force required in seawater is 8.67807 N
Net force on the fin is (freshwater)
[tex]F_n=mg-V_s\rho_{f}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{f}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1000\times 9.81\\\Rightarrow F_n=34.7123\ N[/tex]
The lift force required in a river is 34.7123 N