contestada

How much water should be added to 6 gallons of pure acid in order to obtain the 24% acid solution?
HELP

Respuesta :

frika

Answer:

19 gallons

Step-by-step explanation:

Let x gallons be the amount of water which should be added to 6 gallons of pure acid in order to obtain the 24% acid solution.

Amount of water = x gallons

Amount of pure acid = 6 gallons

Amount of acid solution = x + 6 gallons

Amount of acid in acid solution = 24%

So, there are [tex]0.24(x+6)[/tex] gallons of acid in acid solution.

Hence,

[tex]0.24(x+6)=6[/tex]

Solve this equation. Multiply it by 100:

[tex]24(x+6)=600\\ \\24x+144=600\\ \\24x=600-144\\ \\24x=456\\ \\x=19\ gallons[/tex]

Answer:

19 gallons

Step-by-step explanation:

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

19 gallons

ACCESS MORE
EDU ACCESS