Question

Green checks and red X's are not displayed for the multiple choice portion of this question. In part D of the experiment, a student begins with a beaker containing 10.0 mL of 0.010M HCl solution and adds different volumes of 0.010M NaOH. How many millimoles of acid are initially in the beaker?

Answer 1

Answer:

0.10 mmol

Explanation:

Initially there is only HCl in the beaker. We can calculate the moles of HCl using the following expression:

$M=\frac{n}{V(L)}$

where,

M is the molarity of the solution

n is the moles of the solute

V(L) is the volume of the solution expressed in litres

$M=\frac{n}{V(L)}\\n=M . V(L)= \frac{0.010mol}{L} .10.0 \times 10^{-3} L=1.0 \times 10^{-4}mol$

The milimoles of HCl are:

$1.0 \times 10^{-4}mol.\frac{10^{3}mmol }{1mol} =0.10mmol$