ponhammonda71 ponhammonda71
  • 26-11-2019
  • Chemistry
contestada

how many kilojoules of heat are absorbed when 0.38 grams of chloroethane vaporizes at its normal boiling point?​

Respuesta :

Neetoo
Neetoo Neetoo
  • 03-12-2019

Answer:

1.6 ×10⁻¹ kj

Explanation:

Given data:

Mass of chloroethane = 0.38 g

Heat absorbed = ?

Solution:

Molar mass of chloroethane = 64.51 g/mol

Molar heat of vaporization = 26.4 kj/mol

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 0.38 g/ 64.51 g/mol

Number of moles = 0.006 mol

Heat absorbed:

0.006 mol × 26.4 kj/mol

0.16 kj

or 1.6 ×10⁻¹ kj

Answer Link
jewellowens jewellowens
  • 15-10-2020

Answer:

1.6 ×10⁻¹ kj

Explanation:

Answer Link

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