Question

Pure acid is to be added to a 10% acid solution to obtain 117 L of a 20% acid solution. What amounts of each should be used?

Answer 1

Answer:

A typical mixture equation

:

x + .10(54-x) = .20(54)

x + 5.4 - .10x = 10.8

x - .1x = 10.8 - 5.4

.9x = 5.4

x = 5.4%2F.9

x = 6 L of pure acid to be combined with: 54-6 = 48 L of 10% solution

Step-by-step explanation:

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