Answer:
The Reynolds number is [tex]2.86\times10^{3}[/tex] and flow is transition.
Explanation:
Given that,
Flow rate = 0.01 L/s
Density of water = 1000 kg/m³
Viscosity of water [tex]\eta=8.9\times10^{-4}\ Pa-s[/tex]
Radius = 0.250 cm
We need to calculate the Reynolds number
Using formula of Reynolds number
[tex]N_{R}=\dfrac{2\rho\times v\times r}{\eta}[/tex]
[tex]N_{R}=\dfrac{2\rho\times\dfrac{Q}{A}\times r}{\eta}[/tex]
Where, [tex]\rho[/tex] = water density
[tex]\eta[/tex] = viscosity of water
Q = flow rate
A = area
r = radius
v = velocity
Put the value into the formula
[tex] N_{R}=\dfrac{2\times1000\times\dfrac{0.01\times10^{-3}}{\pi\times(0.250\times10^{-2})^2}\times0.250\times10^{-2}}{8.9\times10^{-4}}[/tex]
[tex]N_{R}=2.86\times10^{3}[/tex]
Reynolds number is below 2,000 then the flow is laminar and when it is above 4,000, then the flow will be turbulent. When the Reynolds number lies between these two limits, then the flow is transition flow.
Hence, The Reynolds number is [tex]2.86\times10^{3}[/tex] and flow is transition.