Answer:
[tex]\dfrac{F}{l}=2\times 10^{-7}\ N/m[/tex]
Explanation:
It is given that,
Distance between two infinitely long wires, d = 1 m
Current flowing in both of the wires, I = 1 A
The magnetic field in a wire is given by :
[tex]B=\dfrac{\mu_oI}{2\pi d}[/tex]
The force per unit length acting on the two infinitely long wires is given by :
[tex]\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}[/tex]
[tex]\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 1^2}{2\pi \times 1}[/tex]
[tex]\dfrac{F}{l}=2\times 10^{-7}\ N/m[/tex]
So, the force acting on the parallel wires is [tex]2\times 10^{-7}\ N/m[/tex]. Hence, this is the required solution.