Answer:
Part 1) The perimeter of triangle ABC is 24 units
Part 2) [tex]y=97\°[/tex]
Step-by-step explanation:
Part 1)
we know that
The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side
The perimeter of triangle ABC is equal to
[tex]P=AB+BC+AC[/tex]
Applying the Midpoint Theorem
Find the measure of AB
[tex]AB=\frac{XZ}{2}[/tex]
substitute given value
[tex]AB=\frac{18}{2}=9\ units[/tex]
Find the measure of BC
[tex]BC=\frac{XY}{2}[/tex]
[tex]XY=2AY[/tex]
substitute given value
[tex]XY=2(7)=14\ units[/tex]
[tex]BC=\frac{14}{2}=7\ units[/tex]
Find the measure of AC
[tex]AC=\frac{YZ}{2}[/tex]
[tex]YZ=2BZ[/tex]
substitute given value
[tex]YZ=2(8)=16\ units[/tex]
[tex]AC=\frac{16}{2}=8\ units[/tex]
Find the perimeter of triangle ABC
[tex]P=9+7+8=24\ units[/tex]
Part 2)
step 1
Find the measure of angle z
Remember that the sum of the interior angles in a triangle must be equal to 180 degrees
[tex]55\°+42\°+z=180\°\\97\°+z=180\°\\z=180\°-97\°\\z=83\°[/tex]
step 2
Find the measure of angle y
we know that
[tex]y+z=180\°[/tex] ----> by supplementary angles (form a linear pair)
substitute the value of z
[tex]y+83\°=180\°[/tex]
[tex]y=180\°-83\°=97\°[/tex]