The area of this circle is 42 π m2. what is the area of a 60° sector of this circle.
this is just to help people :)

Answer:
The Area of sector is 7 [tex]\pi[/tex] m²
Step-by-step explanation:
Given as , for a circle :
The Area of circle = 42 [tex]\pi[/tex] m²
The angle of sector = Ф = 60°
∵ Area of circle = [tex]\pi[/tex] × r² , where r is the radius of circle
or, 42 [tex]\pi[/tex] m² = [tex]\pi[/tex] × r²
∴ r² = 42
Now,
Area of sector = [tex]\pi[/tex] × r² × [tex]\frac{\Theta }{360^{\circ}}[/tex]
Or, Area of sector = [tex]\pi[/tex] × 42 × [tex]\frac{\60° }{360^{\circ}}[/tex]
or, Area of sector = [tex]\pi[/tex] × 42 × [tex]\frac{1}{6}[/tex]
∴ Area of sector = [tex]\pi[/tex] × 7
I.e Area of sector = 7 [tex]\pi[/tex] m²
Hence The Area of sector is 7 [tex]\pi[/tex] m² . Answer