Answer:
Given functions,
[tex]f(x) = 3 - x^2[/tex]
[tex]g(x) = \sqrt{x}+1[/tex]
Since, by the compositions of functions,
1. (g◦f)(x) = g(f(x))
[tex]=g(3-x^2)[/tex]
[tex]=\sqrt{3-x^2}+1[/tex]
Since, (g◦f) is defined,
If 3 - x² ≥ 0
⇒ 3 ≥ x²
⇒ -√3 ≤ x ≤ √3
Thus, Domain = [-√3, √3]
2. (f◦g)(x) = f(g(x))
[tex]=f(\sqrt{x}+1)[/tex]
[tex]=3-(\sqrt{x}+1)^2[/tex]
Since, (g◦f) is defined,
If x ≥ 0
Thus, Domain = [0, ∞)
3. (f◦f)(x) = f(f(x))
[tex]=f(3-x^2)[/tex]
[tex]=3-(3-x^2)^2[/tex]
[tex]=3-9-x^4+6x^2[/tex]
[tex]=-6+6x^2-x^4[/tex]
Since, (f◦f) is a polynomial,
We know that,
A polynomial is defined for all real value of x,
Thus, Domain = (-∞, ∞)