Respuesta :

Answer:

All of these oxides of manganese have a mass percent of metal greater than 50%

Explanation:

Step 1: Data given

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate mass % of Mn in MnO

Molar mass of MnO = 54.94 + 16 = 70.94 g/mol

% Mn = (54.94/70.94)*100 % = 77.45 %

Step 3: Calculate % of Mn in MnO2

Molar mass of MnO2 = 54.94 + 2*16 = 86.94 g/mol

% Mn = (54.94/86.94) * 100% = 63.19 %

Step 4: Calculate % of Mn in Mn2O3

Molar mass of Mn2O3 = 2*54.94 + 3*16 = 157.88 g/mol

% Mn = ((2*54.94)/157.88)*100 % = 69.6 %

All of these oxides of manganese have a mass percent of metal  greater than 50%

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