Question

A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?

Answer 1

The distance covered by the feather is 65.5 m

Explanation:

The motion of the feather is a free-fall motion (affected only by the force of gravity), therefore it is a motion at constant acceleration, and so we can use the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

In this problem, we have

u = 0 is the initial velocity of the feather

t = 9.00 s is the time interval

$a=g=1.62 m/s^2$ is the acceleration of gravity on the Moon

And solving for s, we find the distance covered by the feather in its fall:

$s=0+\frac{1}{2}(1.62)(9.00)^2=65.6 m$

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