Question

Given u⃗ =⟨3,4⟩ and v⃗ =⟨1,2⟩. Let m be the magnitude of vector u⃗ . Find u⃗ +mv⃗ .

Answer 1

Answer:

$\vec u+m\vec v=<8,14>$

Step-by-step explanation:

Being $\vec u$=<3,4> and $\vec v$=<1,2>, we must find

$\vec u+m\vec v$

If m is the magintude of $\vec u$:

$m=\sqrt{a^{2}+b^{2}}$

Where a and b are the components of $\vec u$

$m=\sqrt{3^{2}+4^{2}}=5$

$\vec u+5\vec v=<3,4>+5<1,2>=<3,4>+<5,10>=<8,14>$