Question

Find the secant of both angle A and angle B.

Answer 1

Answer:

The Secant of angle A is 1.083    and

The Secant of angle B is 2.6

Step-by-step explanation:

Given as : The figure is shown as right angle triangle, right angle at c

the measure sides as

Hypotenuse = AB = 26  unit

Base = AC = 24 unit    and

Perpendicular = BC = 10  unit

Now, ∵ Sec Ф = $\frac{\textrm Hypotenuse}{\textrm Base}$

So, From triangle

      Sec A =  $\frac{\textrm Hypotenuse}{\textrm Base}$

Or,  Sec A =  $\frac{\textrm AB}{\textrm AC}$

Or,  Sec A =  $\frac{\textrm 26}{\textrm 24}$

∴     Sec A = 1.083

Again ,

       Sec B =  $\frac{\textrm Hypotenuse}{\textrm Base}$

Or,   Sec B =  $\frac{\textrm AB}{\textrm BC}$

Or,   Sec B =  $\frac{\textrm 26}{\textrm 10}$

∴      Sec B = 2.6

Hence The Secant of angle A is 1.083    and

           The Secant of angle b is 2.6  Answer

Answer 2

Answer:

$\displaystyle 2\frac{3}{5} = sec∠B \\ 1\frac{1}{12} = sec∠A$

Step-by-step explanation:

$\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ \\ \\ \frac{26}{10} = sec∠B → 2\frac{3}{5} = sec∠B \\ \\ \frac{26}{24} = sec∠A → 1\frac{1}{12} = sec∠A$

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