The work done on the gas is 3039 J
Explanation:
The work done to expand of compress a gas at constant pressure is given by
[tex]W=p\Delta V[/tex]
where
p is the pressure of the gas
[tex]\Delta V = V_f - V_i[/tex] is the change in volume of the gas, where
[tex]V_f[/tex] is the final volume
[tex]V_i[/tex] is the initial volume
In this problem we have:
[tex]\Delta V=0.03 m^3[/tex] (change in volume of the gas)
[tex]p=1 atm = 1.013\cdot 10^5 Pa[/tex] is the pressure of the gas
Substituting,
[tex]W=(1.013\cdot 10^5)(0.03)=3039 J[/tex]
Learn more about ideal gases:
brainly.com/question/9321544
brainly.com/question/7316997
brainly.com/question/3658563
#LearnwithBrainly