Answer:
Area = [tex]6 \ yd^2[/tex]; Perimeter = 12 yd
Step-by-step explanation:
Given:
Sides given are 4yd, 5yd and 3 yd
let a = 4yd b = 5yd and c = 3yd
We need to find Area and Perimeter.
Perimeter can be found by adding all sides
Perimeter= sum of all sides = [tex]4yd+5yd+3yd = 12yd[/tex]
Area can be found using Hero's formula which states;
Area = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]
where [tex]s= \frac{a+b+c}{2}=\frac{4+5+3}{2}=\frac{12}{2}=6yd[/tex]
Substituting the values of s and sides we get area as;
Area= [tex]\sqrt{6(6-4)(6-5)(6-3)}= \sqrt{6\times2\times1\times3}=\sqrt{3\times2\times2\times3}=3\times2 = 6yd^2[/tex]
Hence, Area = [tex]6 \ yd^2[/tex]; Perimeter = 12 yd
