Question

A potter is shaping a bowl on a potter's wheel rotating at constant angular speed. The friction force between her hands and the clay is 1.6 N total.(a) How large is her torque on the wheel, if the diameter of the bowl is 12 cm?(b) How long would it take for the potter's wheel to stop if the only torque acting on it is due to the potter's hand? The initial angular velocity of the wheel is 1.6 rev/s, and the moment of inertia of the wheel and the bowl is .11 kg*m^2 Show all work and formulas for best rating.

Answer 1

Answer:

Part A:

T=0.096 N m

Part B:

t=11.525≅11.53 seconds

Explanation:

Part A:

In order to find the torque we will use the following formula:

$T=r*F$

Where T is the torue

r is the radius of bowel

F is the force

$r=\frac{12*10^{-2} }{2} m$

r=0.06 m

$T=0.06*1.6$

T=0.096 N m

Part B:

In order to find how long would it take for potter wheel to sto we will proceed the following way:

T=I*α

Where:

T is the Torque

I is the moment of inertia

α is the angular acceleration

α=T/I

we will take T from art A

α=0.096/0.11

α=0.872 $rad/s^2$

α=ω/t

where:

α is the angular accceleration

ω is angular velocity in rad/s

ω=1.6*2ππ

ω=10.05 rad/s

t=ω/α

$t=\frac{10.05}{0.872}$

t=11.525≅11.53 seconds

It will take 11.53 sec for wheel to stop