Question

A solid cylinder and a thin-walled hollow cylinder have the same radii. They are rolling horizontally toward the bottom of an incline. Assuming there is no friction, what is the maximum height each one reaches (in terms of the variables involved)?

Answer 1

Answer:

height solid / height hollow = 3/4

Explanation:

the height reached is directly proportional to the original KE of the object.

Total KE solid

=$1/2mv^2+1/2\times1/2m r^2(v^2 / r^2 )=3/4mv^2$

Total KE hollow = $1/2mv^2+1/2mr^2(v^2 / r^2 )=mv^2$

height solid / height hollow = 3/4