Question

A mixture of krypton and hydrogen gas is expanded from a volume of 30.0L to a volume of 82.0L , while the pressure is held constant at 14.0atm . Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Answer 1

Answer:

The work done = -73.8 kJ

Explanation:

Step 1: Data given

Volume of 30.0 l expanded tot 82.0 L

Pressure = constant = 14.0 atm

w = -P * (change in V)

w = -14 atm* (82-30)

w = -728 L*atm = -728 * 101.325 J/ 1 L*atm) = -73764.6 J = -73.8 kJ

The sign is - meaning that work is done on the surroundings. The system is losing energy equal to the work done on it.