Answer:
Answered
Explanation:
a) The magnitude of the magnetic flux through the coil before it is rotated is,
[tex]\phi_{initial}= BAsin\theta[/tex]
=BAsin90° = BA
therefore, the magnitude of the magnetic flux= BA
b) The magnitude of the magnetic flux through the coil after it is rotated is, Ф_final = BAsinθ
= BA sin0= 0
therefore, the magnitude of magnetic flux through the coil after it is rotated is, zero.
c) The magnitude of the average emf induced in the coil is,
[tex]\epsilon = N\frac{d\phi}{dt}[/tex]
[tex]\epsilon = N\frac{NBA}{\Delta t}[/tex]
because Ф = BA