Question

A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equally by the two tires. If the pressure in each tire is 7.60 x 10^5 Pa, what is the area of contact between each tire and the ground?

Answer 1

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

given,                                  

weight of the person = 625 N

weight of the bike = 98 N        

Pressure on each Tyre = 7.60 x 10⁵ Pa

Area of contact on each Tyre = ?          

total weight of the system = 625 + 98

                                             = 723 N

Let F be the force on both the Tyre

F + F = W                                    

2 F  = 723                                    

F = 361.5 N                                

F = P A                                            

$A = \dfrac{F}{P}$                          

$A = \dfrac{361.5}{7.60 \times 10^5}$

A = 4.76 x 10⁻⁴ m²

Answer 2

The area of contact between each tire and the ground is 4.76×10⁻⁴ m².

To calculate the area of contact between each tire and the ground, we use the formula of pressure

What is pressure?

Pressure is the force acting perpendicular per unit area to the surface of an object.

Formula:

• P = F/A.............. Equation 1

Where:

• P = Pressure on each tire
• F = Weight acting on each tire
• A = Area of contact between each tire and the ground.

Make A the subject of the equation

• A = F/P.......... Equation 2

From the question,

Given:

• F = (625+98)/2 (supported equally by the two tires)  = 361.5 N
• P = 7.6×10⁵ Pa

Substitute these values into equation 2

• A = 361.5/(7.6×10⁵)

• A = 4.76×10⁻⁴ m²

Hence, The area of contact between each tire and the ground is 4.76×10⁻⁴ m².
Learn more about pressure here:  https://brainly.com/question/24827501