Grams needed to prepare the solution

Answer:
grams of solute = 31.5 g
Explanation:
Given data:
Grams of solute = ?
%m/v = 3%
Volume = 1050 mL
Solution:
grams of solute = 3 g of NH₄Cl / 100 mL × 1050 mL
grams of solute = 0.03 g × 1050
grams of solute = 31.5 g