Answer:
Explanation:
Given
mass of baseball [tex]m=0.15 kg[/tex]
radius of ball [tex]r=3.7 cm[/tex]
angular speed of ball [tex]\omega =45 rad/s[/tex]
linear speed of ball [tex]v=42 m/s[/tex]
Transnational Kinetic Energy is given by
[tex]K.E.=\frac{mv^2}{2}[/tex]
[tex]K.E.=\frac{1}{2}\times 0.15\times 42^2[/tex]
[tex]k.E.=\frac{1}{2}\times 0.15\times 1764[/tex]
[tex] k.E.=132.3 J[/tex]
Considering the ball as solid sphere its moment of inertia is given by
[tex]I=\frac{2}{5}mr^2=\frac{2}{5}\times 0.15\times (0.037)^2[/tex]
[tex]I=8.21\times 10^{-5} kg-m^2[/tex]
Rotational Kinetic Energy
[tex]=\frac{1}{2}\times I\times \omega ^2[/tex]
[tex] =\frac{1}{2}\times 8.21\times 10^{-5}\times 45^2[/tex]
[tex] =\frac{1}{2}\times 8.21\times 10^{-5}\times 2025[/tex]
[tex] =0.0831 J[/tex]