Answer:
Explanation:
Given
inclination [tex]=\beta [/tex]
Assuming radius of sphere is r
Now from Free Body Diagram
[tex]Mg\sin \theta -f_r=Ma[/tex]
where [tex]f_r=friction\ force[/tex]
[tex]a=acceleration\ of\ system[/tex]
Now friction will Provide the Torque
[tex]f_r\times r=I\cdot \alpha [/tex]
where [tex]I=moment\ of\ inertia[/tex]
[tex]\alpha =angular\ acceleration [/tex]
[tex]f_r\times r=\frac{2}{3}Mr^2\times \frac{a}{r}[/tex]
in pure rolling [tex]a=\alpha r[/tex]
[tex]f_r=\frac{2}{3}Ma[/tex]
[tex]mg\sin \beta -\frac{2}{3}Ma=Ma[/tex]
[tex]Mg\sin \beta =\frac{5}{3}Ma[/tex]
[tex]a=\frac{3g\sin \beta }{5}[/tex]