Answer:
0.0196
Explanation:
[tex]\omega[/tex] = Angular speed
m = Mass of wheel = 10 kg
M = Mass of car = 1000 kg
v = Velocity of car
r = Radius of wheels
The wheels are assumed as disks
Rotational kinetic energy in the wheels is given by
[tex]K_w=4\frac{1}{2}I\omega^2[/tex]
Moment of inertia of the wheels is
[tex]I=\frac{1}{2}mr^2[/tex]
[tex]K_w=4\frac{1}{2}mr^2\left(\frac{v}{r}\right)^2\\\Rightarrow K_w=mv^2\\\Rightarrow K=10v^2[/tex]
Kinetic energy of the car
[tex]K_c=\frac{1}{2}Mv^2\\\Rightarrow K_c=\frac{1}{2}\times 1000v^2\\\Rightarrow K_c=500v^2[/tex]
fraction of its total kinetic energy is due to rotation of the wheels about their axles is given by
[tex]\frac{K_w}{K_w+K_c}\\ =\frac{10v^2}{10v^2+500v^2}\\ =0.0196[/tex]
The fraction is 0.0196
As it can be seen that the radius of the wheels cancel out it is not required