Question

it's urgent please help​

Answer 1

Answer:

The equation of  line is  2x-3y=15.

Step-by-step explanation:

Given;

Slope is 2/3 and crosses y axis at (0,-5).

Now, the point = (0,-5) that is $(x_{1},y_{1})$ and the slope of the line = 2/3 which is $m$.

So, now putting the formula for the equation of the line:

$y-y_{1} =m(x-x_{1})$

$y-(-5)=\frac{2}{3}(x-0)$

$y+5=\frac{2}{3}(x-0)$

On solving equation we get :

$3y+15=2x-0$

$15=2x-3y$

$2x-3y=15$

Therefore, the equation of  line is  2x-3y=15.