Respuesta :
Answer:
0.2 M
Explanation:
Let's start by looking at a molecule of sodium sulfate.
Sodium sulfate is made up of sodium and sulfate ions. Sodium(Na) ion is given as Na(+1) where +1 is the valency of the Na atom or the charge on the Na ion. On the other hand sulfate( S[tex]O_{4}[/tex]) ion is represented as S[tex]O_{4}[/tex](-2) where -2 is charge on the sulfate ion. We know that a molecule is electrically neutral. Here the sodium and sulfate ions have charges of +1 and -2 respectively. Hence, for the sodium sulfate which is a compound containing soidum and sulfate ions, there should be 2 ions of sodium and an ion of sulfate, so that it is electrically neutral. Therefore the molecular formula of sodium sulfate is given as : [tex]Na_{2}[/tex][tex]SO_{4}[/tex].
Now we know that one molecule of sodium sulfate has 2 atoms of sodium ions in it. Also, one molar (1M) is 1 mole of the substamce in 1L of soltuion. And 0.1M means 0.1mole of substance (here it is sodium sulfate) in 1L of the solution. 1 molecule of sodium sulfate contains 2 atoms of sodium ions. Therefore, 1 mol of sodium sulfate contains 2 mols of sodium ions. Hence, 0.1mol of sodium sulfate contain 0.2 mols of sodium ions. Hence there are 0.2mols of sodium ions in the solution. Hence the concentration of sodium ion is 0.2M.
