The work done is 200 J
Explanation:
The work done by a force applied to move an object is given by:
[tex]W= F d cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, assuming that the force applied by the workers is parallel to the direction of motion of the crate, we have:
F = 10.0 N
d = 20.0 m
[tex]\theta=0^{\circ}[/tex]
Therefore, the work done is:
[tex]W=(10.0)(20.0)(cos 0)=200 J[/tex]
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