The final vertical velocity of the object is 705.6 m
Explanation:
Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of
[tex]g=9.8 m/s^2[/tex]
towards the ground due to gravity.
Therefore, we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final vertical velocity
u is the initial vertical velocity
[tex]a=g[/tex] is the acceleration
t is the time
Since the object is dropped,
u = 0
Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:
[tex]v=0+(9.8)(72)=705.6 m/s[/tex]
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